The resistance of the wire of length 250m is 1 ohm. If the resistivity of the material of wire is 1.6×10^-8 ohm meter, find the area of cross section of the wire. How much does the resistance change if the diameter is doubled?
Answers
Answered by
0
Two coils, X of 12000 turns and Y f 15000 turns, lie in parallel planes so that 45% of the flux
produced by coil X links coil Y. A current of 5 A in X produces 0.05Wb while the same current in Y
produces 0.075Wb. Calculate
Answered by
0
hey bro/gal.
since, resistance = resistivity× length / area
=) 1 = 1.6 * 10^-8 * 250/ A
=) A = 400*10^-8 = 4*10^-6 m²
=) if diameter is doubled then area will become 4A.
=) new Area = A' = 4*4*10^-6 = 16*10^-6 m²
=) R' = 1.6*10^-8 * 250/ 16*10^-6
= 1/4 ohm.
since, resistance = resistivity× length / area
=) 1 = 1.6 * 10^-8 * 250/ A
=) A = 400*10^-8 = 4*10^-6 m²
=) if diameter is doubled then area will become 4A.
=) new Area = A' = 4*4*10^-6 = 16*10^-6 m²
=) R' = 1.6*10^-8 * 250/ 16*10^-6
= 1/4 ohm.
theCHAMPisReady:
right ans or wrong?
Similar questions