the resistance of two conductor in series is 40 ohm & the resistance 6.4 ohm when connected in parallel. Find the resistance of individual conductor
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Req in series = R1+R2=40+4+=80ohm
a resistance of 6.4 ohm is connected in parallel then
then Req=R1R2/R!+R2
Req=80*6.4/80+6.4
=8*64/86.4
=5.92 ohm
approximately 6 ohm is the net resistance of this individual circuit
a resistance of 6.4 ohm is connected in parallel then
then Req=R1R2/R!+R2
Req=80*6.4/80+6.4
=8*64/86.4
=5.92 ohm
approximately 6 ohm is the net resistance of this individual circuit
vivek4:
32 & 8 ohm
x+ y =40 & 1/x+1/y=1/6.5 and then solve it linear equation in two variable
no lamba its about 10 line
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