Question

the resistance of two conductors in parallel is 12 ohm and in series 50 ohm find the resistance of each conductor

Answer 1

Hope it helps uh!!!!!!!!!!!!!!!

Answer 2

Answer:

The value of each resistance will be 30 ohm and 20 ohm.

Explanation:

Given that,

Resistance in parallel = 12 ohm

Resistance in series = 50 ohm

Let us consider two resistance are R_{1} and R_{2}.

We know that,

The resistance in parallel

$R_{p}=\dfrac{R_{1}R_{2}}{R_{1}+R_{2}}$.....(I)

The resistance in series

$R_{s}=R_{1}+R_{2}$.....(II)

Multiplying equation (I) and equation (II)

$R_{p}R_{s}=R_{1}R_{2}$

$R_{1}R_{2}=12\times50$

$R_{1}R_{2}=600$

$R_{1}=\dfrac{600}{R_{2}}$

Put the value of $R_{1}$ in equation (II)

$R_{s}=\dfrac{600}{R_{2}}+R_{2}$

$R_{2}^2-50R_{2}+600=0$

$R_{2}=30\Omega,20\Omega$

Hence, The value of each resistance will be 30 ohm and 20 ohm.