Question

The resistance of two conductors in series is 18 ohm and 4 ohm when connected in parallel.The individual resistance of the conductors are​

Answer 1

Answer:

let resistance be a,b

a+b=18. (1)

1/a+1/b=1/4

ab/a+b=4

by (1)

ab/18= 4

ab=72

a=72/b

a+b=18

72/b+b=18

b^2-18b+72=0

Answer 2

hey buddy,

here is your answer