Question

The resistance r=v/i were v=(100±5)v, i=(10±0.2)a.Find the percentage error in r

Answer 1

Answer:

Explanation:

v=(100+-5)a

I=(10+-0.2)a

R=V/I =100/10=10Ω

ΔR/R=+_[ ΔV/V+  ΔI/I]

=+_[5/100+0.2/10]

=+_[7/100]

=+_0.07

ΔR=R*0.07

=+_0.07*10

=0.7 ohms

Percentage error  ΔR/R*100=+_0.07*100=+_7 percent

Answer 2

HLO MATE HERE U GO

R = V/I

Delta R / R = Delta V/v + Delta I /I

==> 5/ 100 + 02./10

==> 0.5 + 0.02 = 0.07

⭐. Relative error in R = 0.07

⭐. percentage error in R = 0.07 × 100 = 7%.