Question

The relation between time and distance is equals to alpha x square + beta x alpha and beta are constants the retardation is

Answer 1

Answer:

Explanation:

Please note that probably you forgot the LHS while writing the relation between t and x.  

I think the correct equation would be t = ax^2+bx. Please let me know if this wrong.  

 

So, if t = ax^2+bx

then, differentiate both side with respect to time (t)  

dt/dt = 2ax.dx/dt + b.dx/dt  

1 = 2axv + bv  

v.(2ax + b) = 1  

(2ax + b) = 1/v  

Again differentiate both side with respect to time (t)  

2a.dx/dt = -v -2 . dv/dt  

2av = v -2 . acceleration  

acceleration = -2av ^3

Hence, retardation= 2av^ 3