Question

Thermal efficiency of a standard otto cycle for a compression ratio of 5.5 will be

Answer 1

Answer:

Explanation:

For an Otto Cycle, the efficiency is given as : 1−(1/(rγ−1)),where r = Compression ratio and γ = Ratio of Specific Heats.

Assuming, γ = 1.4 for Standard Air Cycle, the result comes out as 49.4344%