Science, asked by kashishparveen2738, 11 months ago

The resistances in the two arms of the meter bridge are 5 Ω and R Ω respectively.

Answers

Answered by joshnajustin7a
0

Answer:

=

100−l

1

l

1

R/2

5

=

100−1.6l

1

1.6l

1

Solving l

1

=25cm and R=15Ω

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