Physics, asked by vikram5019, 8 months ago

The resistor of 5 ohm,10ohm,30 ohm,in parallel combination have been connected to a baatery of 12 v calculate A) the current through each resistors B) the total current in the curciut C) the total circuit resistance

Answers

Answered by priyanshuanand1454
0

Explanation:

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Answered by lordmridul69
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Answer: (a) Now by ohms law,

I=V/R

Now let as there are three resistance such that let us name them, R1=5 OHM, R2= 10 OHM, R3= 30 OHM

Now is always same so V will be same in all resistences.

But current will be different then

I1=12/5,

I2=12/10,

I3=12/30,.... (1)

Now total current which is =I1+I2+I3.... (2)

Now by solving 1 we get

(b) Total current =2.4+1.2+0.4

Then, Total current is = 4.0Ampere.

(c) now by applying again ohms law,

We get, R= total current /potential difference.

Then R=I/V

R=4/12 =1/3 ohms or 0.33 ohms

Explanation:

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