Biology, asked by yjenn2906, 6 months ago

the respiratory tubes formed by the division of wind pipe before enter the lungs

Answers

Answered by abcd17867

2

Explanation:

Your trachea is divided into 2 air passages called bronchial tubes. One bronchial tube leads to the left lung, the other to the right lung.

Answered by ankitgupta82

5

Explanation:

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:

ʏᴏᴜʀ ᴛʀᴀᴄʜᴇᴀ ɪs ᴅɪᴠɪᴅᴇᴅ ɪɴᴛᴏ ᴀɪʀ ᴘᴀssᴀɢᴇs ᴄᴀʟʟᴇᴅ ʙʀᴏɴᴄʜɪᴀʟ ᴛᴜʙᴇs. ᴏɴᴇ ʙʀᴏɴᴄʜɪᴀʟ ᴛᴜʙᴇ ʟᴇᴀᴅs ᴛᴏ ᴛʜᴇ ʟᴇғᴛ ʟᴜɴɢ, ᴛʜᴇ ᴏᴛʜᴇʀ ᴛᴏ ᴛʜᴇ ʀɪɢʜᴛ ʟᴜɴɢ.

ᴍᴀʀᴋ ᴀs ʙʀᴀɪɴʟɪsᴛ ❤

Previous Question

Next Question

Similar questions

English, 2 months ago

character sketch of mr Gupta in price of flowers...with the hint given below: responsible, sympathetic, helping mentality, humanitarian, trustworthy,generous,does not like to lie, sensible,treates Maggie with respect,sincere. *need help as soon as possible pls...*no jocking...

Math, 2 months ago

Let f(x) = cos(px)+sin x be periodic, then p must be Positive real number o Negative real number Rational Prime...

Social Sciences, 2 months ago

who is the wise president of india?

English, 6 months ago

How do mosses and liverworts reproduce?

Math, 6 months ago

From the sum of 3x² - 4x + 2 and (-5x² + 8x - 7) subtract (-6x² + 7x-5) please give the ans .... please dont give the ans like (hsjsudgdjdjdjijensjetc) and like ???????? and don't write like that i dont know yarr sorry..... if you don't know so please don't ans...

Chemistry, 11 months ago

An ester (A) with molecular fomula, C₉H₁₀O₂ was treated with excess of CH₃MgBr and the complex so formed was treated with H₂SO₄ to give an olefin (B). Ozonolysis of (B) gave a ketone with molecular formula C₈H₈O which shows positive iodoform test. The structure of (A) is (a) C₆H₅COOC₂H₅ (b) C₂H₅COOC₆H₅ (c) H₃COCH₂COC₆H₅ (d) p—H₃CO—C₆H₄ —COCH₃...

Chemistry, 11 months ago

The above shown polymer is obtained when a carbonyl compound is allowed to stand. It is a white solid. The polymer is (a) Trioxane (b) Formose (c) Paraformaldehyde (d) Metaldehyde...

Chemistry, 11 months ago

The increasing order of the rate of HCN addition to compound A – D is (A) HCHO (B) CH₃COCH₃ (C) PhCOCH₃ (D) PhCOPh (a) D < C < B < A (b) C < D < B < A (c) A < B < C < D (d) D < B < C < A...