Question

The rest mass of a proton is 1.6×10–27 kg. What will be its mass while in motion with a velocity 0.8C ?​

Answer 1

Answer:

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Answer 2

$The total energy can be calculated using the relativistic form of the mass-energy equivalence formula, E=mc2E=mc2</p><p></p><p>The relativistic form is as below:</p><p></p><p>E=γ×m×c2E=γ×m×c2</p><p></p><p>Where γγ is the Lorentz factor arising from Lorentz transformations, and is equal to:</p><p></p><p>γ=11−v2c2√γ=11−v2c2</p><p></p><p>Here, v is the velocity which in this case is 0.6c0.6c</p><p></p><p>Therefore, γγ becomes</p><p></p><p>γ=11−(0.6×c)2c2√γ=11−(0.6×c)2c2</p><p></p><p>γ=11−0.36×c2c2√γ=11−0.36×c2c2</p><p></p><p>γ=11−0.36√γ=11−0.36</p><p></p><p>γ=10.64√γ=10.64</p><p></p><p>γ=10.8γ=10.8</p><p></p><p>γ=1.25γ=1.25</p><p></p><p>Therefore, the total energy, EE is now:</p><p></p><p>E=1.25×1.67×10−27×2997924582E=1.25×1.67×10−27×2997924582</p><p></p><p>E=1.876151435613099938×10−10JE=1.876151435613099938×10−10J</p><p></p><p>E=1.172GeV</p><p></p><p></p><p>$

The total energy can be calculated using the relativistic form of the mass-energy equivalence formula, E=mc2

The relativistic form is as below:

E=γ×m×c2

Where γ is the Lorentz factor arising from Lorentz transformations, and is equal to:

γ=11−v2c2√

Here, v is the velocity which in this case is 0.6c

Therefore, γ becomes

γ=11−(0.6×c)2c2√

γ=11−0.36×c2c2√

γ=11−0.36√

γ=10.64√

γ=10.8

γ=1.25

Therefore, the total energy, E is now:

E=1.25×1.67×10−27×2997924582

E=1.876151435613099938×10−10J

E=1.172Gev

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