The result of dividing a number of two digits by the number with digits reversed is 5/6.If the difference between the digits is 1, Find the number.
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Let us assume, x and y are the two digits of the two-digit number and Let y > x
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
(10x + y) / (10y + x) = 5/6
6 (10x + y) = 5 (10y + x)
60x + 6y = 50y + 5x
55x - 44y = 0
5x - 4y = 0 ---------1
Also given:
y - x = 1 ------------2
Multiply equation 1 by 4
4y - 4x = 4 ------------------3
Adding equation 1 and e4quation 3
x = 4
Therefore, y = 1 + x = 1 + 4 = 5
The two-digit number = 10x + y = 10 * 4 + 5 = 45
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
(10x + y) / (10y + x) = 5/6
6 (10x + y) = 5 (10y + x)
60x + 6y = 50y + 5x
55x - 44y = 0
5x - 4y = 0 ---------1
Also given:
y - x = 1 ------------2
Multiply equation 1 by 4
4y - 4x = 4 ------------------3
Adding equation 1 and e4quation 3
x = 4
Therefore, y = 1 + x = 1 + 4 = 5
The two-digit number = 10x + y = 10 * 4 + 5 = 45
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