Question

the resultant of the two vector having magnitude 5 and 4 is 1. what is magnitude of cross product. ​

Answer 1

Answer:

Let A = 5

and B = 4 .

Then , A+B = 1

we know | A+B | =under root (A^2 + B^2 + 2AB cos theta)

1= under root(5^2 + 4^2 + 2* 4 *5 cos theta )

1= under root (25+16+40costheta)

1=under root(41 + 40cos theta)

Squaring both the sides

1 = 41+ 40cos theta

-40= 40 cos theta

Cos theta= -1

Theta = 180degree

Now,

Cross product of A and B = AB sintheta

= AB sin 180

= AB * 0

= 0

so the answer is 0.

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Answer 2

Here is your answer ,i.e.,0