The resultant of two forces A+B and A-B is a force (3A^2+B^2)
the angle between two given forces is
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Answer:
C
=
A
+
B
D
=
A
−
B
∠
C
D
=θ
∠
A
B
=φ
R=
C
2
+D
2
+2CDcosθ
=
(A
2
+B
2
+2ABcosφ)+(A
2
+B
2
−2ABcosφ)+2(A
2
−B
2
)cosθ
=
2A
2
+2B
2
+2(A
2
−B
2
)cosθ
R=
3A
2
+B
2
⇒cosθ=
2
1
⇒θ=
3
π
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