Science, asked by anamikamahato, 1 month ago

The resultant of two forces A+B and A-B is a force (3A^2+B^2)

the angle between two given forces is​

Answers

Answered by DEEPTHI09
0

Answer:

C

=

A

+

B

D

=

A

B

C

D

A

B

R=

C

2

+D

2

+2CDcosθ

=

(A

2

+B

2

+2ABcosφ)+(A

2

+B

2

−2ABcosφ)+2(A

2

−B

2

)cosθ

=

2A

2

+2B

2

+2(A

2

−B

2

)cosθ

R=

3A

2

+B

2

⇒cosθ=

2

1

⇒θ=

3

π

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