Math, asked by srujan8691, 21 days ago

the resultant of two forces(a bar + b bar) and (a bar- b bar) is a force √3a^2+b^2 the angle between a bar+ b bar and a bar - b bar​

Answers

Answered by Anonymous
109

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C = A + B

D = A - B

 \sqrt{CD}  = Φ

 \sqrt{AB}  = φ

 R =   \sqrt{ {C}^{2}  +  {D}^{2}  + 2CD} \:  cosΦ

 =  \sqrt{ {A}^{2} +  {B}^{2}  + 2AB \:  \cosΦ  + {A}^{2} + {B}^{2}  + 2AB}

 =  \sqrt{ 2{A}^{2}  + 2 {B}^{2}  + 2({A}^{2}   -   {B}^{2})cosΦ}

 R =  \sqrt{3 {A}^{2}  +  {B}^{2} }

➠ \: cosΦ =  \frac{1}{2}

➠Φ =  \frac{\pi}{3}

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