The resultant of two forces p and q is R if one of the force is reversed indirection the resultant becomes R' show that R²+R'²=2(P²+Q²)
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R = ✓(p^2 + q^2 + 2pqcos@). (@ is the angle b/w p and q)
R' = ✓(p^2 + q^2 - 2pqcos@)
squaring both the equation adding them
R^2 + R'^2 = p^2 + q^2 + 2pqcos@ + p^2 + q^2 - 2pqcos@
= 2p^2 + 2q^2
R' = ✓(p^2 + q^2 - 2pqcos@)
squaring both the equation adding them
R^2 + R'^2 = p^2 + q^2 + 2pqcos@ + p^2 + q^2 - 2pqcos@
= 2p^2 + 2q^2
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