The resultant of two vectors ū and v vector is perpendicular to vector ū and its magnitude is equal to
Half of the magnitude of vector v. Find the angle between ū and v.
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Explanation:Resultant of 2 vectors 'u' and 'v' is given as
=?{u�+v�+2uvcos?}
Hence
v/2 =?{u�+v�+2uvcos?}
?v� =4{u�+v�+2uvcos?}.....(i)
Angle '?' of resultant with 'u' is given by
tan? =(vsin?)/(u+vcos?)
Since ?=90�
u+vcos?=0 i.e u=?vcos?....(ii)
from (i) and (ii), we get
v� =4{(?vcos?)�+v�+2(?vcos?)vcos?}
? v� =4{v�cos�?)+v�?2v�cos�?
?v� =4v�{1?cos�?}
i.e 1=4?4cos�?}
cos cos�?=3/4 or
cos?=�?3/2 or
Since the resultant is less than 'u' hence angle ?> 90�.
Hence cos?=??3/2 and ?=150�
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