Physics, asked by SUCCESS16, 1 year ago

The resultant value of resistances each of value r ohms when connected in parallel is x, when these resistances are connected in series the resultant resistance is :
nx
n power 2x
x/n
x/n power 2

with explanation


SUCCESS16: their is no diagram for q

Answers

Answered by Kalmax
6
1/Re=1/r +1/r +1/r...n/r
1/Re= n/r (in case of parallel)
Re=r/n ----> x=r/n
r=xn
so now in case of series
it would be n2 times of resultant resistance x.
Re= r+r+.....nr
Re=nr (as r=xn)
so,
Re=n*xn
Re=n2x

SUCCESS16: wrong
Kalmax: how
Answered by Agastya0606
1

The correct answer is option (b) n power 2x.

Given,

The resultant value of resistances each of value r ohms when connected in parallel is x.

To Find,

The resultant resistance when these resistances are connected in parallel.

Solution,

The formula for calculating the resultant resistance is

1/R' = 1/r+1/r+1/r+...n times

1/x = n/r

x = r/n

r = nx

Now, the resultant resistance when resistances are connected in series

R net = r+r+r+...n times

R net = nr

Substituting the value of r as nx

R net = n(nx) = n²x

Hence, the resultant resistance is n²x.

#SPJ3

Similar questions