The resultant value of resistances each of value r ohms when connected in parallel is x, when these resistances are connected in series the resultant resistance is :
nx
n power 2x
x/n
x/n power 2
with explanation
SUCCESS16:
their is no diagram for q
Answers
Answered by
6
1/Re=1/r +1/r +1/r...n/r
1/Re= n/r (in case of parallel)
Re=r/n ----> x=r/n
r=xn
so now in case of series
it would be n2 times of resultant resistance x.
Re= r+r+.....nr
Re=nr (as r=xn)
so,
Re=n*xn
Re=n2x
1/Re= n/r (in case of parallel)
Re=r/n ----> x=r/n
r=xn
so now in case of series
it would be n2 times of resultant resistance x.
Re= r+r+.....nr
Re=nr (as r=xn)
so,
Re=n*xn
Re=n2x
Answered by
1
The correct answer is option (b) n power 2x.
Given,
The resultant value of resistances each of value r ohms when connected in parallel is x.
To Find,
The resultant resistance when these resistances are connected in parallel.
Solution,
The formula for calculating the resultant resistance is
1/R' = 1/r+1/r+1/r+...n times
1/x = n/r
x = r/n
r = nx
Now, the resultant resistance when resistances are connected in series
R net = r+r+r+...n times
R net = nr
Substituting the value of r as nx
R net = n(nx) = n²x
Hence, the resultant resistance is n²x.
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