Question

The revolution per second for the electron present in 3rd orbit of He+ ion is


9.73 × 1014


6.57 × 1015


9.73 × 1016


1.52 × 1016

Answer 1

Answer:

n=number of revolution per second=

circumferenceoforbit

velocityofe

−

V

n

=2.188×10

6

×

n

z

μ

n

=0.529A

∙

×

z

n

2

Putting z=1 and n=2

V

2

=2.188×10

6

×

2

1

μ

2

=0.529×4×10

−10

=2.116×10

−10

m

n=

2×3.14×2.116×10

−10

1.094×10

6

=0.082×10

16

=8.2×10

14

revolution/sec