Question

The right angle triangle of which of side containing the right angle or 6.3 cm and 10 cm in length is made to turn around on the longer side find the volume of a solid is generated also find it is also find its curved surface area

Answer 1

Use Pythagoras theorem to find one side of triangle n then use the formulas of volume n curved surface area to find them

Answer 2

Answer:

=> Note

Area = (1/2)•(Base)(Perpendicular)

Pythagoras theorem :- In a right-angled. In the triangle, the square of the hypotenuse is equal to the sum of square of the other two perpendicular sides.

h^2 = b^2 + p^2

Perimeter of a polygon is given by the sum of the lengths of its all sides.

Solution :

It is given that,

The difference between the sides at the right angles in a right-angled triangle is 14 cm.

Thus,

Let the base of the given right-angled triangle be x cm.

And,

Let the perpendicular of the given right-angle triangle be (x+14) cm.

Also,

It is given that;

The area of triangle is 120 cm^2

=> Area = 120

=> (1/2) (Base)(Perpendicular) = 120

=> (Base)(Perpendicular) = 120•2

=> (Base)(Perpendicular) = 240

=> x(x+14) = 240

=> x^2 + 14x = 240

=> x^2 + 14x - 240 = 0

=> x^2 + 24x - 10x - 240 = 0

=> x(x + 24) - 10(x + 24) = 0

=> (x + 24)(x - 10) = 0

=> x = -24 , 10

Now,

Length can't be negative, thus x = -24

is rejected value.

Therefore,

The appropriate value is x = 10.

Thus,

Base of the triangle = x cm = 10 cm

Perpendicular of the triangle

= (x+14) cm

= (10+14) cm

= 24 cm

Now,

Applying Pythagoras theorem in the given triangle,

We get;

=> h^2 = b^2 + p^2

=> h^2 = (10)^2 + (24)^2

=> h^2 = 100 + 576

=> h^2 = 676

=> h = √676

=> h = 26

Hence,

Hypotenuse of the triangle = 26 cm.

Here,

The perimeter of the triangle will be given by;

=> Perimeter = b + p + h

=> Perimeter = (10 + 24 + 26) cm

=> Perimeter = 60 cm.

Hence;

The perimeter of the given right-angled triangle is 60cm.