Science, asked by yash233118, 17 days ago

The rigid bar BDE is supported by two links AB and
CD. Link AB is made of aluminum (E = 70 GPa) and
has a cross-sectional area of 500 mm?; link CD is
made of steel (E = 200 GPa) and has a cross-sectional
area of 600 mm². For the 30-KN force shown,
determine the deflection (a) of B, (b) of D, (C) of E.
OC
бв
= 0.514 nu
B' Op = 0.300 mm
IND
E
B
6 = 0.514 mm
D
8g&o= 0.300 mm/
30 kN
04 m
0.3 m
D
E
(200 mm - x)
de = 1.928 mm,
B
E'
400 mm
200 mm
-0.4m
0.2 m
Prepared by E Vinaragavan, vijayare milodu.in

Answers

Answered by narayanarvindpatil
1

Answer:

I don't understand question

Answered by kbonggol514176
0

Answer:
For Delta Ab= 0.514mm
For Delta DC=0.300mm
For Delta E = 1.928mm

Explanation:

Just find the internal force for every link AB and DC using statics
Then for E use integral to find the answer

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