Question

The RMS velocity of an ideal gas at 27 degree celsius is 0.3 M per second its RMS velocity at 927 degrees celsius is

Answer 1

Answer:

0.6 m/s.

Explanation:

Since, the first temperature T1 is given as 27°C = 300 K and the  second temperature T2 is 927°C = 1200 K . So, we can find the velocity relation by using the formulae or relation of velocity(here rms velocity) is directly proportional to the  square root of the (Absolute Temperature).

So, from the relation we get that v1 / v2 = √(T1 / T2).

So, on substituting the values we will get 0.3 / v = √(300 / 1200).

0.3 / v = 1 / 2 .

So, the RMS(root mean square) velocity will be v = 0.6 m/s .

So, the RMS velocity at the temperature of 927°C or 1200K is 0.6 m/s.

Answer 2

Answer:

the answer is 0.6m/s I hope it helps you