Question

The rod AC of a TV disc antenna is fixed
at right angles to the wall AB and a rod
CD is supporting the disc as shown in
Fig. 4. If AC=1.5 m long and CD = 3 m,
find (i) tan 0 (ii) sec @ + cosec 0.​

Answer 1

Step-by-step explanation:

Given The rod AC of a TV disc antenna is fixed  at right angles to the wall AB and a rod  CD is supporting the disc as shown in  Fig. 4. If AC=1.5 m long and CD = 3 m,  find (i) tan θ (ii) sec θ + cosec θ.

• The figure is a right angled triangle ACD with AC as base, CD as hypotenuse and AD the opposite side
• From triangle ACD, AC = 1.5 cm, CD = 3 cm
• Triangle ACD is a right angled triangle. From Pythagoras theorem we get
• CD^2 = AD^2 + AC^2
• Or AD^2 = CD^2 – AC^2
•               = 3^2 – 1.5^2
•              = 9 – 2.25
•              = 6.75
• Therefore AD = √6.75
•                       = 2.5 cm
• Now tan theta = AC / AD  
•                           = 1.5 / 2.5
•                          = 3/5
• Also sec theta + cosec theta = CD / AD + CD / AC
•                                                = 3/2.5 + 3/1.5
•                                                 = 16 / 5

Reference link will be

https://brainly.in/question/2454587

Answer 2

Answer:

the above answer is correct