Question

The rod made up of plane carbon steel subjected to force 5kN and the permissible tensile stress 80N/mm2 then the diameter of rod comes out to

be

Answer

A. 8.92mm

B. 9.82cm

C.2.98cm

D. 2.8​

Answer 1

Answer:

c 2.98cm it is very stress=force/area

area=3.14*dia^2/4

Explanation:

Answer 2

The diameter of the rod will be 8.92 mm (A)

Given:

Force $=5KN$

Tensile strength $=80N/mm^{2}$

To find:

The diameter of the rod.

Solution:

Step 1

In solid mechanics, strength is theoretically the Pressure and is given by the force applied on the object upon the area of contact between the system applying the force and the object.

Mathematically,     Strength $S=\frac{F}{A}$

Substituting the given values in the equation, we get

$80=\frac{5*10^{3} }{A}$

$A=\frac{5000}{80}$

$A=6.25mm^{2}$

Step 2

We know,

Area = π$R^{2}$

Where, R is the radius of the rod.

π$R^{2} =6.25$

$R^{2}=\frac{6.25*7}{22}$

$R^{2}=19.88$

$R=4.49mm$

Hence, the diameter will be $D=2$ × $R$

$D=2$ × $4.49$

$D=8.92mm$

Final answer:

Hence, the diameter of the rod will be 8.92 mm (A).