Question

The root mean square velocity of one mole of a monoatomic gas having molar mass M is $u_{r.m.s.}$. The relation between the average kinetic energy (E) of the gas and $u_{r.m.s.}$ is
(a) $u_{r.m.s.}$ = $\sqrt{\frac{3E}{2M}}$
(b) $u_{r.m.s.}$ = $\sqrt{\frac{2E}{3M}}$
(c) $u_{r.m.s.}$ = $\sqrt{\frac{2E}{M}}$
(d) $u_{r.m.s.}$ = $\sqrt{\frac{E}{3M}}$

Answer 1

Answer:

Hope u got it

Explanation:

Answer 2

its (C)... hope this helps you have a nice day