Question

The root of 5(x-3)-4(x-2)=0

Answer 1

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The root of 5(x-3)-4(x-2)=0

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$5(x - 3) - 4(x - 2)$

$5x - 15 - 4x + 8 = 0$

$x - 15 + 8 = 0$

$x - 7 = 0$

$\red{ x=7 }$

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