Question

The root of each of the following quadratic equation are real and equation.find k:kx(x-2)+6=0

Answer 1

Step-by-step explanation:

Kx(X-2)+6=0

Kx^2-2kx+6=0

Kx^2-2kx+6=0

Discriminant =b^2-4ac

=(-2k)^2-4(6)(k)

=4k^2-24k

We know, for equal root, Discriminant =0

Hence, 4k^2-24k=0

4k(k-6)=0

4k=0 or k-6=0

K=0/4=0 or k=6

K=6 or 0