Math, asked by ramkatkar, 1 year ago

the root of equation x^2+x-p(p+1)=0 where p is constant

Answers

Answered by abhi743

0

_p(p+1) is constant and consistent(1) is coefficient

abhi743: sorry x (1) cofficient

Answered by s1983

1

the answer is
p,-p-1
please comment on this
thank you

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