Question

the root of qudratic equation y2_16y+63=0
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Answer 1

Answer:

y= 7 and 9

Step-by-step explanation:

${y}^{2} - 16y + 63 = 0 \\ {y}^{2} - 9y - 7y + 63 = 0 \\ y(y - 9) - 7(y - 9) = 0 \\ (y - 7)(y - 9) = 0 \\ y = 7 \: and \: y = 9$