Question

The root of the equation px^+qx+ r=0
qx^–2 x√pr + q = 0 are real and equal, then
(a) p/q=q/r
(b)q=r
(c)2q=±√pr
(d)p=q​

Answer 1

Step-by-step explanation:

Equation px2+2qx+r=0 and qx2−2prx+q=0 have real roots, then 

b2−4ac≥0 for both equations

From first

4q2−4pr≥0⇒q2≥pr    ...............(1)

and from second 

4(pr)−4q2≥0 (for real root)

⇒pr≥q2                           ...............(2)

From (1) and (2), we get result q2=pr