Question

The root of x²+kx+k=0 are real dbd equal,find k
please urgent ​

Answer 1

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The roots of x² + kx + k = 0 are real and equal, find k.

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Given:-The roots of x² + kx + k  real & equal  then,

b²  − 4ac = 0

(k)² −4 (1) (k) = 0

k² −4k = 0

k (k−4) = 0

k = 0 or,

k = 4

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Answer 2

Answer:

• Given:-The roots of x² + kx + k real & equal then,

b² − 4ac = 0

(k)² −4 (1) (k) = 0

k² −4k = 0

k (k−4) = 0

k = 0 or,

k = 4 Ans.