what is the nature of line which passes through the points P(7,-2) ,Q(-3,-3),R(2.5,-3),S(-4.5,-2).
Answers
The cell I have to use is a
Given :
P(7,-2) ,Q(-3,-3),
R(2.5,-3),S(-4.5,-2).
To Find : nature of line which passes through the points
Solution:
P(7,-2) ,Q(-3,-3),
Slope = ( -3 - (-2))/(-3 - 7)
= (-1 )/(-10)
= 1/10
y + 3 = (1/10)(x + 3)
=> 10y + 30 = x + 3
=> x = 10y + 27
R(2.5,-3),S(-4.5,-2).
Slope = -1/7
y + 3 = -(1/7)(x - 5/2)
=> 7y + 21 = - x + 5/2
=> x + 7y + 37/2 = 0
x = 10y + 27
x + 7y + 37/2 = 0
y = - 91/34
x = 8/34
Lines PQ & RS are intersecting
P(7,-2) ,S(-4.5,-2)
y coordinate are same hence PS parallels to x axis
Q(-3,-3),R(2.5,-3),
y coordinate are same hence QR parallels to x axis
PS || QR
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