Question

The roots α and β of the quadratic equation x2

-5x+3(k-1)=0 are such that α-

β=1. Find the value k.
Please answer as soon as possible ​

Answer 1

$⏩ \: { x }^{2} - 5x + 3(k - 1)$

we know that:

$multiple \: of \: roots = \frac{ c}{a}$

$a b = \frac{3(k - 1)}{1}$

$a = 3(k - 1)b$

{ Put a in a - b = 1 }

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

Hence, the value of ‘k’ is founded .