Question

The roots ax2+bx+c=0,a≠0  are equal, then the roots are​

Answer 1

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Given equation,

$\sf a {x}^{2} + bx + c = 0$

And,

The roots of the given equation are equal

So,

$\sf \Delta = 0$

i.e.,Discrimant is equal to zero.

So,

$\sf x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

$\sf = \frac{ - b}{2a}$

Thus,

Roots are,

$\sf = \frac{ - b}{2a}$

Answer 2

Answer:

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