Math, asked by dhirajshintre2004, 6 months ago

The roots of

2 + + = 0 are real and equal, find k.​

Answers

Answered by itsbrainlybiswa
4

Answer:The value of k = 9/2 = 4.5

Step-by-step explanation:f the roots of a quadratic equation are real and equal then

Discriminant(b^2 - 4ac) of  Quadratic equation is zero.

It is given a quadratic equation

2x2- 6x + k = 0,

the roots of  are real and equal.

Therefore Discriminant of  Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of  2x2- 6x + k = 0,

a = 2

b = -6

c = k

To find the value of k

b^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36

k = 36/8 = 9 /2 = 4.5

hope it helps u

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Answered by Aparanasherma
1

Discriminant ( b ^ 2 - 4 ac ) of Quadratic equation is zero . 2 x 2 - 6x + k = 0 , the roots of are real and equal . Therefore Discriminant of Quadratic equation is zero .......

I hope this answer will setisfy you , please mark as the brain list .......

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