the roots of 3x2-kx+12=0 are equal then find k
Answers
Answered by
27
Hi !
p(x) = 3x² - kx + 12
a = 3 , b = -k , c = 12
as the roots are equal ,
b² - 4ac = 0
(-k)² - 4 x 3 x 12 = 0
k² - 144 = 0
k² = 144
k = √144
k = 12
∴ Value of k = 12
p(x) = 3x² - kx + 12
a = 3 , b = -k , c = 12
as the roots are equal ,
b² - 4ac = 0
(-k)² - 4 x 3 x 12 = 0
k² - 144 = 0
k² = 144
k = √144
k = 12
∴ Value of k = 12
Answered by
3
Answer:
The correct answer is 12
Step-by-step explanation:
Given: p(x) = 3x² - kx + 12 =0
To find: value of k
3x² - kx + 12
After comparing to quadratic equation, we get the values of A,B,C
a = 3 , b = -k , c = 12
as the roots are equal ,
b² - 4ac = 0
put the values of a,b,c in above formula,
(-k)² - 4 x 3 x 12 = 0
k² - 144 = 0
k² = 144
k = √144
after takingsquare root,
k = 12
therefore, the Value of k = 12
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