Question

The roots of a quadratic equation given below are
​

Answer 1

Answer:

not real

Step-by-step explanation:

 Discriminant of ax^2 + bx + c - 0 is given by b^2 - 4ac, here,  

a = 5, b = - 5, c = 5.

So,

⇒ Discriminant = (-4)^2 - 4(5*5)

            = 16 - 4( 25 )

            = 16 - 100

            =  - 84

As - 84 < 0, roots are not real.

Answer 2

CORRECT QUESTION:

Roots of the quadratic polynomial 5x² - 4x + 5 are

• Real & equal

• Real & unequal

• Not real

• Non real & equal

SOLUTION:

Finding the roots of the given quadratic polynomial by using quadratic formula

x = - b±√b² - 4ac/2a

Where

• b : coefficient of x = - 4
• a : coefficient of x² = 5
• c : constant term = 5

Substituting the values we have

→ x = -( - 4) ± √(- 4)² - 4( 5 )( 5 )/2( 5 )

→ x = 4±√ 16 - 100/10

→ x = 4 ± (√84)i/10

Roots are complex

Hence, roots are not real [ option ( c ) ] is your answer.