Question

the roots of ax² - 26x + c = 0, then a³B³ + a²B³+a³b² equals​

Answer 1

Step-by-step explanation:

e of Ax^2+2Bx+C=0 then prove that (b^2-ac),(B^2-AC)=(a,A)^2.

e of Ax^2+2Bx+C=0 then prove that (b^2-ac),(B^2-AC)=(a,A)^2.Missing: 26x + ‎a³B³ + ‎a²B³+ ‎a³b²