Question

the roots of eq. x^2+x-p(p+1)=0 where p is constant​

Answer 1

Answer:

the roots are - ( p) and (-1 - p).

Step-by-step explanation:

Equation is:

x2 + x - p(p + 1) = 0

Here it is in the form of ax2 + bx + c = 0

:; a = 1 , b = 1 , c = -p2 - p

D = b2 - 4ac

= 1 - 4 * 1 * (-p2 - p)

= 1 + 4p2 + 4p

Now, alpha = - b + root D / 2a

-1 + 2p + 1 /2

= 2p / 2 , = p

and then, beta = -b - root D / 2a

= -1 -2p - 1 /2

= -2 - 2p /2

-2 (1 + p) / 2

= -1 - p

Therefore, the roots are - ( p) and (-1 - p)

I hope it will helps you friend