Question

The roots of quadratic equation x2-3x+7=0 are. ​

Answer 1

Step-by-step explanation:

D^2=b^2-4ac

= (-3)^2-4×1×7

= 9-28

=-19

here d is negative and less than zero so roots are not real and they will not exist

Answer 2

Answer:

(3±√-19) / 2

Step-by-step explanation:

Given:

x²-3x+7 = 0

Solution:

a=1, b=-3, c=7

x = (-b±√b²-4ac) / 2a

  = [3±√(-3)²-4(1)(7)] / 2(1)

  = [3±√9 - 28] / 2

x = [3±√-19] /2