The roots of quadratic equestion 5x2-4x+5=0 are
Answers
Answered by
1
Answer:
4±2✓21i/10
Step-by-step explanation:
i assume that equation is 5x²-4x+5=0
by pluggin this in quadratic formula
=> x=-b±✓(b²-4ac)/2a
where a=5
b=-4
and c=5
we get
4±✓(16-100)/10
=> 4±✓-84 /10
=> 4±2✓21i/10
Similar questions