The roots of root 3 x²+10x-8root 3=0
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Given quadratic equation :-
√3x² + 10x - 8√3 = 0
Splitting the middle term,
√3x² + 12x - 2x - 8√3 = 0
Rewriting the terms,
√3x² + (√3x) (4√3) - 2x - 2 × (4√3) = 0
√3x (x + 4√3) -2 (x + 4√3) = 0
(x + 4√3) (√3x - 2) = 0
x + 4√3 = 0
x = -4√3 are roots of given quadratic equation.
Answered by
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• Roots of the given equation are 2/√3 and -4√3.
Given :-
• A quadratic equation √3x² + 10x - 8√3 = 0
To Find :-
• Roots of the given equation.
★ By splitting the middle term, we get :-
» √3x² + 12x - 2x - 8√3 = 0
• Rewriting the terms, we get :-
» √3x (x + 4√3) - 2 (x + 4√3) = 0
➪ (√3x - 2) (x + 4√3) = 0
• √3x - 2 = 0
➪ x = 2/√3
• x + 4√3 = 0
➪ x = - 4√3
★ Hence, the roots of the equation are
x = 2/√3 or -4√3.
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