Math, asked by nitish21012006, 9 months ago

The roots of root 3 x²+10x-8root 3=0​

Answers

Answered by Anonymous
13

\huge\bold{Answer:-}

Given quadratic equation :-

√3x² + 10x - 8√3 = 0

Splitting the middle term,

√3x² + 12x - 2x - 8√3 = 0

Rewriting the terms,

√3x² + (√3x) (4√3) - 2x - 2 × (4√3) = 0

√3x (x + 4√3) -2 (x + 4√3) = 0

(x + 4√3) (√3x - 2) = 0

x + 4√3 = 0

x = -4√3 are roots of given quadratic equation.

Answered by Anonymous
10

\large{\boxed{\bf{AnswEr}}}

• Roots of the given equation are 2/√3 and -4√3.

Given :-

• A quadratic equation √3x² + 10x - 8√3 = 0

To Find :-

• Roots of the given equation.

\large{\boxed{\bf{Solution}}}

★ By splitting the middle term, we get :-

» 3x² + 12x - 2x - 83 = 0

Rewriting the terms, we get :-

» √3x (x + 4√3) - 2 (x + 4√3) = 0

(√3x - 2) (x + 4√3) = 0

3x - 2 = 0

x = 2/√3

x + 43 = 0

x = - 4√3

★ Hence, the roots of the equation are

x = 2/√3 or -4√3.

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