The roots of root3x^2+10x-8root3=0 are
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Given:
root3x^2+10x-8root3=0
To find:
The roots of root3x^2+10x-8root3=0
Solution:
From given, we have,
A quadratic equation given by, √3x² + 10x - 8√3 = 0
a = √3 b = 10 c = -8√3
substitute these values in the formula
x = [-b ±√(b² - 4ac)]/2a
x = [-10 ±√(10² - 4 × √3 × (-8√3))]/2(√3)
upon further solving, we get the roots of the equation as,
x = 2√3/3 and x = -4√3
Therefore, the roots of √3x² + 10x - 8√3 = 0 are x = 2√3/3 and x = -4√3
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