Math, asked by shalini4057, 10 months ago

the roots of the equation 4/3x^2-2x+3/4​

Answers

Answered by kailashmannem
7

Answer:

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Answered by mysticd
2

 Given \: Quadratic \: Equation : \\\frac{4}{3}x^{2} - 2x + \frac{3}{4} = 0

/* Multiplying each term by 12 , we get */

 \frac{12 \times 4}{3}x^{2} -12 \times  2x + \frac{12 \times 3}{4} = 0

 \implies 16x^{2} - 24x + 9 = 0

\implies (4x)^{2} - 2 \times (4x) \times 3 + 3^{2} = 0

\implies ( 4x - 3 )^{2} = 0

\implies ( 4x - 3 )(4x-3)= 0

\implies  4x - 3 = 0 \:Or \: 4x-3= 0

\implies  4x = 3  \:Or \: 4x = 3

\implies  x = \frac{3}{4}  \:Or \: x = \frac{3}{4}

Therefore.,

 \green { \frac{3}{4} \:and \: \frac{3}{4}  \: are }\\\green { roots \: of \: given \: Quadratic \: Equation }

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