Question

the roots of the equation 4/3x^2-2x+3/4​

Answer 1

Answer:

Hope it helps you...........

Answer 2

$Given \: Quadratic \: Equation : \\\frac{4}{3}x^{2} - 2x + \frac{3}{4} = 0$

/* Multiplying each term by 12 , we get */

$\frac{12 \times 4}{3}x^{2} -12 \times 2x + \frac{12 \times 3}{4} = 0$

$\implies 16x^{2} - 24x + 9 = 0$

$\implies (4x)^{2} - 2 \times (4x) \times 3 + 3^{2} = 0$

$\implies ( 4x - 3 )^{2} = 0$

$\implies ( 4x - 3 )(4x-3)= 0$

$\implies 4x - 3 = 0 \:Or \: 4x-3= 0$

$\implies 4x = 3 \:Or \: 4x = 3$

$\implies x = \frac{3}{4} \:Or \: x = \frac{3}{4}$

Therefore.,

$\green { \frac{3}{4} \:and \: \frac{3}{4} \: are }\\\green { roots \: of \: given \: Quadratic \: Equation }$

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