the roots of the equation 5x^2+10x-7=0 are
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5x² + 10x -7 = 0
x² + 10/5 x - 7/5 = 0
x² +2x = 7/5
x² + 2x +1 = 1+7/5
(x +1)² = 12/5
take square root both sides
x + 1 = ± 2√3/√5
x = -1 ± 2√3/√5
=( -√5 ±2√3)/√5
x² + 10/5 x - 7/5 = 0
x² +2x = 7/5
x² + 2x +1 = 1+7/5
(x +1)² = 12/5
take square root both sides
x + 1 = ± 2√3/√5
x = -1 ± 2√3/√5
=( -√5 ±2√3)/√5
Ramu111:
the answer is opposite signs
means
(-root 5 + 2root 3) /(root 5) or (-root5 - 2 root 3) /(root5)
:-)
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0
hi,
5x^2+10x-7=0
x^2+10/5 x-7/5=0
x^2+2x-7/5=0
5x^2+10x-7=0
x^2+10/5 x-7/5=0
x^2+2x-7/5=0
incomplete solution finish it
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