Math, asked by dhanalaxmimandadi, 6 months ago

the roots of the equation (x+1/x)square=4+3/2(x-1/x)are

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Answers

Answered by rimpasingharoy654
0

Answer:

(x+1)²/x² = 4+(3/2)(x-1)/x

or, 2 (x+1)² = 8x² + 3(x-1)x

or, 2(x²+2x+1) = 8x² +3x²-3x

or, 9x²-7x-2=0

or, x = {7±√(49+72)}/18

or, x = (7±11)/18

or, x= 1, -2/9

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