Question

The roots of the given equation (p-q){{x}^{2}}+(q-r)x+(r-p)=0
are [RPET 1986; MP PET 1999; Pb. CET 2004]
A) \frac{p-q}{r-p},1 B) \frac{q-r}{p-q},1 C) \frac{r-p}{p-q},1 D) 1,\frac{q-r}{p-q}

Answer 1

HEYA!!!


HERE IS YOUR ANSWER,


⇔ The roots of the given equation (p-q){{x}^{2}}+(q-r)x+(r-p)=0
are :

→ $C) (\frac{r-p}{p-q},1)$


HOPE IT HELPS YOU,
THANK YOU. ^_^