Question

the roots of the quadractic equation 2x²-2root2x+1​

Answer 1

Answer:

(1/√2 ; 1/√2)

Step-by-step explanation:

hey mate there is ur answer

= 2x²-2√2x+1

= 2x²-√2x-√2x+1

= √2x(√2x-1) -1(√2x-1)

= (√2x-1)(√2x-1)

(√2x-1) = 0

x= 1/√2

(√2x-1)= 0

x = 1/√2

(1/√2 ; 1/√2)

i hope it helps you

Answer 2

Given

• 2x² - 2√2x + 1

To find

• Roots of the quadratic equation.

Solution

• By Elimination method

$\tt:\implies\: \: \: \: \: \: \: \: {2x^2 - \sqrt{2}x - \sqrt{2}x + 1}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\sqrt{2}x(\sqrt{2}x - 1) - 1(\sqrt{2}x - 1) }$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {(\sqrt{2}x - 1) (\sqrt{2}x - 1)}$

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★ Roots are

$\tt\longmapsto{x = \dfrac{1}{\sqrt{2}}}$

⠀

$\tt\longmapsto{x = \dfrac{1}{\sqrt{2}}}$

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