Question

The roots of the quadratic equation: kr^2 + 4x + 1 = 0 are real and equal, then find k.​

Answer 1

Answer:

Given: quadratic equation kx

2

+4x+1=0, has real and distinct roots

To find the value of k

Sol: An equation has real and distinct roots if the discriminant b

2

−4ac>0

In the given equation, a=k,b=4,c=1

Therefore the discriminant is 4

2

−4(k)(1)>0

16−4k>0

⟹4k<16

Therefore, k<4

Step-by-step explanation:

hope this will helpful to you

Answer 2

Answer:

k=4

Step-by-step explanation:

The given quadratic equation is kx^2+4x+1

Here , a=k, b=4 and c=1

As we know that D=b^2 - 4ac

Putting the value of a=k, b=4 and c=1

D=(4)^2 -4 (k) (1)

=16-4k

The equation will have real and equal roots,if D=O Thus*

16-4R =O

4R = 16

R=16/4 4/1=4

Ans k =4