The roots of x²+kx+k=0 are real and equal, find k.
(A) 0
(B) 4
(C) 0 or 4
(D) 2
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Answered by
76
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Here is your answer!
_______________________________
QUADRATIC EQUATION :
x²+kx+k=0
On comparing it with ax²+bx+c=0
We get,
a=1, b=k and c=k
_______________________________
For real and equal roots,
Discriminant (D) =0
b²- 4ac=0
k²- 4×1×k=0
k²- 4k=0
k(k-4)=0
So, k=0 or k=4
______________________________
So, option (C) is correct i.e., 0 or 4.
______________________________
Hope it's satisfactory!
Here is your answer!
_______________________________
QUADRATIC EQUATION :
x²+kx+k=0
On comparing it with ax²+bx+c=0
We get,
a=1, b=k and c=k
_______________________________
For real and equal roots,
Discriminant (D) =0
b²- 4ac=0
k²- 4×1×k=0
k²- 4k=0
k(k-4)=0
So, k=0 or k=4
______________________________
So, option (C) is correct i.e., 0 or 4.
______________________________
Hope it's satisfactory!
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