Math, asked by StarTbia, 1 year ago

The roots of x²+kx+k=0 are real and equal, find k.
(A) 0
(B) 4
(C) 0 or 4
(D) 2

Answers

Answered by Anonymous
76
Hey!

Here is your answer!
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QUADRATIC EQUATION :

x²+kx+k=0

On comparing it with ax²+bx+c=0

We get,

a=1, b=k and c=k
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For real and equal roots,

Discriminant (D) =0

b²- 4ac=0

k²- 4×1×k=0

k²- 4k=0

k(k-4)=0

So, k=0 or k=4
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So, option (C) is correct i.e., 0 or 4.
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Hope it's satisfactory!
Answered by samikshaa28
7

Answer:

HERE'S YOUR ANSWER.

HOPE IT HELPS

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